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0.25g^2=2g
We move all terms to the left:
0.25g^2-(2g)=0
a = 0.25; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·0.25·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*0.25}=\frac{0}{0.5} =0 $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*0.25}=\frac{4}{0.5} =8 $
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